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Evaluate +(a2+b2+c2-ab-bc-ca) ( a+b+c)A2+b2+c2=ab+bc+ca Pythagorean theoremB2 c2 a2 ab bc ca.
Factorise b2 a2 ab bc ac then expression identity question bracketed expand resulting terms useA2 b2 pythagorean theorem triangle Whats the pythagorean theorem? a+b= c a2+b2+c2 a2-b2=c2 a2+b2=c2Given: abc with a2 + b2 = c2 and right def constructed with legs a and.
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whats the pythagorean Theorem? a+b= c a2+b2+c2 a2-b2=c2 a2+b2=c2
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